HOTSPOT
You have a DHCP server named Server1 that runs Windows Server 2012 R2.
On Server1, you run the commands as shown in the exhibit. (Click the Exhibit button.)
To answer, complete each statement according to the information presented in the exhibit.
Each correct selection is worth one point.
Answer: 
Explanation:
Is this a trick question?
Should the first answer not be 172.16.1.250?
I believe the presented answer is correct…here’s why:
When you run the following command it creates a DNS entry for 192.168.15.0:
Set-DhcpServerv4Optionvalue -DnsServer 192.168.15.250 -Router 192.168.15.1 -ScopeId 192.168.15.0
Since the reservation placed for AABBCCDDEEFF was for the 192.168.10.0 address, the DNS entry for the reservation does not apply when AABBCCDDEEFF connects to the 192.168.15.0 network.
math
excluded 9 addresses (192.168.15.30 – 192.168.15.21)
address range (192.168.15.11 – 192.168.15.230)
230 -11 = 219
ans = 219 – 9—————————————-|^
ans = 210
Your result is correct, but math is not.
Scope and exclusion ranges include borders, so:
11 to 230 = 220 addresses
21 to 30 = 10 addresses
220 – 10 = 210
i do not understand the second line of the output.
it says start range 192.168.16.11 and end range 192.168.15.200.
what i am missing?
Its the scope for the 192.168.15.0 network
It says “192.168.15.11” not “192.168.16.11”
I’ve just spent ages looking at this and thinking how is the answer not 172.16.1.250. Then I re-read the question ‘when the computer is connected to the 192.168.15’ therefore the first answer is 192.168.15.250 (as this is the DNS address for the 192.168.15. range).
192.168.15 .250 is the only address in the 192.168.15.0 address range
scope range is 192.168.15 .11 – 192.168.15.130 = 220 addresses
9 of these are in the exclusion range 192.168.15 .21 – 192.168.15.30 = 10
so 210 addresses available for leasing
Correction: scope range is 192.168.15 .11 – 192.168.15.230 = 220 addresses
Correction no 2: 10 of these are in the exclusion range 192.168.15 .21 – 192.168.15.30 = 10
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Answers:
DNS Server: 192.168.15.250
192.168.15.0/24 can lease out 210 addresses.
The first part of the question “A computer that has a mac address of AABBCCDDEEFF…
” is irrelevant to the answer.
Since it says it’s connected to the 192.168.15.0 network, we can tell by the DHCP Powershell commands that that network was given a DNS scope option of 192.18.15.250…
Scope options OVERRIDE Server options. The last command shown to us will not overwrite the Scope option of the command above it.
The 172.16.1.250 address is only assigned to the one machine we reserved. Which has nothing to do with the question.
Regarding the address leases, it is simple math. since the scope is 192.168.15.11 – 230
230 – 11 = 219
The question also has a reservation scope of 192.168.15.21 – 30
30 – 21 = 9
Then subtract both
(230 – 11) – (30 -21 ) =
= 219 – 9
= 210
Simple enough?
Can that machine AABBCCDDEEFF bypass the reservation(192.168.10.x) and connect to 192.168.15.x instead in real world?
Yes, you connect it to 15.x and it will just get the IP from the 15.x scope (but in 10.x it will always get the 10.15 IP).