A company has a forest with 4 sites. Subnets are as follows:
MainOffice 172.16.1.0 Subnet: 255.255.255.0 Gateway 172.16.1.254
Site1 192.168.12.0 Subnet: 255.255.255.0
Site 2 192.168.13.0 Subnet: 255.255.255.0
Site 3 192.168.14.0 Subnet: 255.255.255.0
Site 4 192.168.15.0 Subnet: 255.255.255.0
You add a new server to the MainOffice and it needs to be able to communicate to all sites.
Which route command would you run?
A.
route add -p 192.168.8.0 netmask 255.255.252.0 172.16.1.254
B.
route add -p 192.168.0.0 netmask 255.255.248.0 172.16.1.254
C.
route add -p 192.168.12.0 netmask 255.255.252.0 172.16.1.254
D.
route add -p 192.168.12.0 netmask 255.255.240.0 172.16.1.254
Dup of 562
To do the route summarization you can transform the octet that changes in common for each IP range to bits.
So the 12 until 15 you have:
00001100
00001101
00001110
00001111
Observe that from left to right the numbers repeat until here “000011” so the route that summaries them must count the first 16 bits plus these 6 = 22 bits /22 mask which in decimal is 252.
That’s five sites.