Which Transact-SQL query should you use?

You create a table that has the StudentCode, SubjectCode, and Marks columns to record
mid-year marks for students. The table has marks obtained by 50 students for various
subjects.
You need to ensure that the top half of the students arranged by their average marks must
be given a rank of 1 and the remaining students must be given a rank of 2.
Which Transact-SQL query should you use?

You create a table that has the StudentCode, SubjectCode, and Marks columns to record
mid-year marks for students. The table has marks obtained by 50 students for various
subjects.
You need to ensure that the top half of the students arranged by their average marks must
be given a rank of 1 and the remaining students must be given a rank of 2.
Which Transact-SQL query should you use?

A.
SELECT StudentCode as Code,
RANK() OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode

B.
SELECT Id, Name, Marks,
DENSE_RANK() OVER (ORDER BY Marks DESC) AS Rank
FROM StudentMarks

C.
SELECT StudentCode as Code,
DENSE_RANK() OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode

D.
SELECT StudentCode as Code,
NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode

E.
SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1

F.
SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1

G.
SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1

H.
SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1



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Bhupender Singh

Bhupender Singh

D is correct one.