You need to develop the application to meet the requirements

DRAG DROP
You are developing a web application that retrievesdata from a web service. The data being retrieved is a custom binary datatype named bint. The data can also be represented in XML. Two existing methods named parseXml() and parseBint() are defined on the page.
The application must:
Retrieve and parse data from the web service by using binary format if possible
Retrieve and parse the data from the web service by using XML when binary format is not possible
You need to develop the application to meet the requirements.
What should you do? (To answer, drag the appropriate code segment to the correct location. Each code segment may be used once, more than once, or not atall. You may need to drag the split bar between panes or scroll to view content.)

DRAG DROP
You are developing a web application that retrievesdata from a web service. The data being retrieved is a custom binary datatype named bint. The data can also be represented in XML. Two existing methods named parseXml() and parseBint() are defined on the page.
The application must:
Retrieve and parse data from the web service by using binary format if possible
Retrieve and parse the data from the web service by using XML when binary format is not possible
You need to develop the application to meet the requirements.
What should you do? (To answer, drag the appropriate code segment to the correct location. Each code segment may be used once, more than once, or not atall. You may need to drag the split bar between panes or scroll to view content.)

A.

Explanation:



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herub

herub

Why everybody choose requestResponseHeader() ??. It should be if(type==’application/bint’)..
http://api.jquery.com/jQuery.ajax/

kasper

kasper

I think it’s because datatype/type should contain only “bint” (which is not an available answer), but the contenttype/accepts should contain “application/bint”.

karen

karen

respuesta cual seria .. :S

some random dude from interwebs

some random dude from interwebs

it’s not
uri: ‘/’
but should be url: ‘/’, uri is unknown parameter and will be ignored.

let me explain what is type argument with this code snippet:

$.ajax({
// ..
dataType: ‘penis’,
dataFilter: function(data, type) {
alert(type); // nsfw!
// ..
}
})

Neto

Neto

accepts: ‘application/bint, text/xml’,

if(request.getResponseHeader(“Content-Type”) == “application/bint”)