You need to write a console application that meets the following requirements:
If the application is compiled in Debug mode, the console output must display Entering
debug mode.
If the application is compiled in Release mode, the console output must display Entering
release mode.
Which code should you use?
A.
Option A
B.
Option B
C.
Option C
D.
Option D
Explanation:
#elif lets you create a compound conditional directive. The #elif expression will be evaluated
if neither the preceding #if (C# Reference) nor any preceding, optional, #elif directive
expressions evaluate to true. If a #elif expression evaluates to true, the compiler evaluates
all the code between the #elif and the next conditional directive. For example:
#define VC7
//…
#if debug
Console.Writeline(“Debug build”);
#elif VC7
Console.Writeline(“Visual Studio 7”);
#endif
Incorrect:
Not B:* System.Reflection.Assembly.GetExecutingAssembly Method
Gets the assembly that contains the code that is currently executing.
* Assembly.IsDefined Method
Indicates whether or not a specified attribute has been applied to the assembly.
* System.Dignostics.Debugger Class
Enables communication with a debugger.
Property: IsAttached
Gets a value that indicates whether a debugger is attached to the process.
D
Release is not defined! Should be #elseif (!DEBUG) or gust #else
#define Release
using System;
{…}
#if(DEBUG)
Console.WriteLine(“DEBUG”);
#elif(Release)
Console.WriteLine(“Release”);
#endif
Console.ReadLine();
}
D
Yes, what j suggest can work. Non of the existing options is going to work. Another solution would be:
#if (DEBUG)
Console.WriteLine(“Debug mode”);
#else
Console.WriteLine(“release mode”);
#endif