You use Microsoft Visual Studio 2010 and Microsoft .NET Framework 4.0 to create an application.
The application contains the following XML fragment:
<ApplicationMenu>
<MenuItem name=”File”>
<MenuItem name=”New”>
<MenuItem name=”Project” />
<MenuItem name=”Web Site” />
</MenuItem>
<MenuItem name=”Open”>
<MenuItem name=”Project” />
<MenuItem name=”Web Site” />
</MenuItem>
<MenuItem name=”Save” />
</MenuItem>
<MenuItem name=”Edit”>
<MenuItem name=”Cut” />
<MenuItem name=”Copy” />
<MenuItem name=”Paste” />
</MenuItem>
<MenuItem name=”Help”>
<MenuItem name=”Help” />
<MenuItem name=”About” />
</MenuItem>
</ApplicationMenu>
The application queries the XML fragment by using the XmlDocument class. You need to select all the descendant
elements of the MenuItem element that has its name attribute as File. Which XPath expression should you use?
A.
//*[@name=’File’][name()=’MenuItem’]
B.
/ApplicationMenu/MenuItem[‘File’]//MenuItem
C.
/ApplicationMenu/MenuItem/descendant::MenuItem[‘File’]
D.
/ApplicationMenu/MenuItem[@name=’File’]/descendant::MenuItem
Explanation:
XPath Examples:
XmlNodeList nodes = doc.SelectNodes(“/ApplicationMenu/MenuItem[@name=’File’]/descendant::MenuItem”); // 01 == 02
XmlNodeList nodes = doc.SelectNodes(“/ApplicationMenu/MenuItem[@name=’File’]//MenuItem”); // 02 == 01
XmlNodeList nodes = doc.SelectNodes(“/ApplicationMenu/MenuItem[2]/descendant::MenuItem”); // 03
XmlNodeList nodes = doc.SelectNodes(“/ApplicationMenu/MenuItem[last()]/descendant::MenuItem”); // 04
XmlNodeList nodes = doc.SelectNodes(“/ApplicationMenu/MenuItem/descendant::MenuItem[/ApplicationMenu/MenuItem/@name=@name]”); // 05
XmlNodeList nodes = doc.SelectNodes(“/ApplicationMenu/MenuItem/*”); // 06
XmlNodeList nodes = doc.SelectNodes(“/ApplicationMenu/MenuItem/descendant::*[@Description]”); //07
XmlNodeList nodes = doc.SelectNodes(“/ApplicationMenu/MenuItem[MenuItem][position()=2]”); // 08 == 09
XmlNodeList nodes = doc.SelectNodes(“/ApplicationMenu/MenuItem[MenuItem and position()=2]”); // 09 == 08
XmlNodeList nodes = doc.SelectNodes(“/ApplicationMenu/MenuItem[SubMenu or position()=2]”); // 10XPath Examples
(http://msdn.microsoft.com/en-us/library/ms256086.aspx)
I verified the answer using online XPath tester:
http://www.freeformatter.com/xpath-tester.html#ad-output
Here’s the output I got using answer D:
Element=”
Element=”
Element=”
MenuItem name=”New”
MenuItem name=”Project”
MenuItem name=”Web Site”