How should you configure DHCP2?

Your network contains two DHCP servers. The DHCP servers are named DHCP1 and DHCP2. The internal
network contains 1,000 DHCP client computers that are located on a single subnet. A router separates the
internal network from the Internet. The router has a single IP address on the internal interface.
DHCP1 has the following scope information:
Starting IP address: 172.16.0.1
Ending IP address: 172.16.7.254
Subnet mask: 255.255.240.0
You need to provide a fault tolerant DHCP infrastructure that supports the client computers on the internal
network. In the event that a DHCP server fails, allclient computers must be able to obtain a valid IPaddress.
How should you configure DHCP2?

Your network contains two DHCP servers. The DHCP servers are named DHCP1 and DHCP2. The internal
network contains 1,000 DHCP client computers that are located on a single subnet. A router separates the
internal network from the Internet. The router has a single IP address on the internal interface.
DHCP1 has the following scope information:
Starting IP address: 172.16.0.1
Ending IP address: 172.16.7.254
Subnet mask: 255.255.240.0
You need to provide a fault tolerant DHCP infrastructure that supports the client computers on the internal
network. In the event that a DHCP server fails, allclient computers must be able to obtain a valid IPaddress.
How should you configure DHCP2?

A.
Create a scope for the subnet 172.16.0.0/20. Configure the scope to use a starting IP address of 172.16.8.1
and an ending IP address of 172.16.15.254.

B.
Create a scope for the subnet 172.16.0.0/21. Configure the scope to use a starting IP address of 172.16.0.1
and an ending IP address of 172.16.15.254.

C.
Create a scope for the subnet 172.16.8.0/21. Configure the scope to use a starting IP address of 172.16.8.1
and an ending IP address of 172.16.10.254.

D.
Create a scope for the subnet 172.17.0.0/16. Configure the scope to use a starting IP address of 172.17.0.1
and an ending IP address of 172.17.255.254.

Explanation:
Network 255.255.240.0 = /20 -> 4096-2 addresses
255.255.255.0 = /24 -> 256-2 addresses
255.255.254.0 = /23 -> 512-2 addresses
255.255.252.0 = /22 -> 1024-2 addresses
255.255.248.0 = /21 -> 2048-2 addresses
IP address 172.16.0.1 to 172.16.7.254 -> 8*256 -2 =2048-2 addresses
There are 2048-2 addresses left belind.
Option B (172.16.0.0/21) is ruled out because 172.16.0.1 to 172.16.15.254 are belonged to /20 (not /21)
network
Option C (172.16.8.0/21) is ruled out because 172.16.8.1 to 172.16.10.254 contain 3*256-2 = 766
addresses only (insufficient for 1,000 clients)
Option D (172.17.0.0) is ruled out because of different network 172.17.0.0/16 (vs 172.16.0.0/20)



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