CORRECT TEXT
There are three locations in a school district of a large city: ROUTER -M, ROUTER -W and
ROUTER -U. The network connection between two of these locations has already functioned.
Configure the ROUTER -M router IP addresses on the E0 and S0 interfaces so that the E0
receives the first usable subnet while the S0 receives the second usable subnet from the network
192.168.160.0/28. Both interfaces would receive the last available ip address on the proper
subnet.
NotE. The OSPF process must be configured to allow interfaces in specific subnets to
participate in the routing process.
Answer: See the explanation
Explanation:
ROUTER-M> enable
PassworD. Cisco
ROUTER-M# config t
ROUTER-M(config)# interface e0
ROUTER-M(config-if)# ip address 192.168.160.14 255.255.255.240
ROUTER-M(config-if)# no shutdown
ROUTER -M(config-if)# exit
ROUTER -M(config)# interface s0
ROUTER-M(config-if)# ip address 192.168.160.30 255.255.255.240
ROUTER-M(config-if)# no shutdown
ROUTER-M(config-if)# end
ROUTER-M# copy run start
Anyone knows how the 2 IP addresses are derived? I don’t get it. thks.
The question gives you the network 192.168.160.0/28. It says the E0 interface gets the last host IP in the first subnet. The S0 gets the last host IP in the 2nd subnet. A /28 is a 16 block. (255.255.255.240 is the subnet mask). So the first network is 192.168.160.0. The Second subnet is 192.168.160.16. The IP address for E0 then would be 192.168.160.14. That’s the last usable host IP in the first subnet. The S0 interface would be 192.168.160.30. That’s the last usable host IP the second subnet.
What does this question got to do with OSPF configuration? I didn’t see any configurations on the router related to OSPF?