The following configuration is applied to a Layer 2 Switch:
interface fastethernet 0/4
switchport mode access
switchport port-security
switchport port-security mac-address 0000.1111.1111
switchport port-security maximum 2
swithcport port-security
What is the result of the above configuration being applied to the switch?
A.
A host with a mac address of 0000.1111.1111 and up to two other hosts can connect to
FastEthernet 0/4 simultaneously
B.
A host with a mac address of 0000.1111.1111 and one other host can connect to Fast Ethernet
0/4 simultaneously
C.
Violating addresses are dropped and no record of the violation is kept
D.
The switch can send an SNMP message to the network management station
E.
The port is effectively shutdown
Explanation:
http://www.cisco.com/en/US/docs/switches/lan/catalyst4500/12.2/20ewa/configuration/guide/port_
sec.html
Admin: The question only asks for one answer, so why is D selected as correct?
good question thought I was seeing things. both seem to be correct answers:
switchport port-security mac-address 0000.1111.1111
switchport port-security maximum 2
would mean 2 computers can connect with one being that specific mac address 0000.1111.1111
sorry looks like I did not answer your question completely. no other violation = default which is 1) shutdown & 2) logs via snmp or syslog