Which address range efficiently summarizes the routing table of the addresses for router Main?
A.
172.16.0.0./21
B.
172.16.0.0./20
C.
172.16.0.0./16
D.
172.16.0.0/18
Which address range efficiently summarizes the routing table of the addresses for router Main?
A.
172.16.0.0./21
B.
172.16.0.0./20
C.
172.16.0.0./16
D.
172.16.0.0/18
To summarize these networks efficiently we need to find out a network that “covers” from 172.16.1.0 -> 172.16.13.0 (including 13 networks < 16). So we need to use 4 bits (24 = 16). Notice that we have to move the borrowed bits to the left (not right) because we are summarizing.
The network 172.16.0.0 belongs to class B with a default subnet mask of /16 but in this case it has been subnetted with a subnet mask of /24 (we can guess because 172.16.1.0, 172.16.2.0, 172.16.3.0… are different networks).
Therefore “move 4 bits to the left” of “/24″ will give us “/20″