Which outgoing interface will router RTD choose for packets to the 192.168.0.0/24 network, and why?

Refer to the exhibit.

Router RTB is performing one-way redistribution from RIP to OSPF. Which outgoing interface will
router RTD choose for packets to the 192.168.0.0/24 network, and why?

A.
Fa0/1, because OSPF is a link-state routing protocol

B.
Fa0/0, because RIP is a distance vector protocol

C.
Fa0/0, because RIP has a higher administrative distance

D.
Fa0/0, because OSPF has a lower administrative distance

E.
Fa0/1, because OSPF has a lower administrative distance

F.
Fa0/1, because RIP has a lower administrative distance

Explanation:
RTD has information in both topologies RIP and OSPF, and it has to elect which one is better, and
the tie-breaker is AD (adminitrative Distance)
Rip pointing to the RIP domain (left i dont remember the interfaces please post the picture)
OSPF pointing to the OSPF domain (to the right)
RIP –> AD = 120
OSPF –> AD = 110
Lower is Better in AD so the correct answer depends on the exibit but i remeber that’s the one to

the right (to the OSPF domain and the longer path)