What is the result?

Given:

class Overloading {
int x(double d) {
System.out.println(“one”);
return 0;
}
String x(double d) {
System.out.println(“two”);
return null;
}
double x(double d) {
System.out.println(“three”);
return 0.0;
}
public static void main(String[] args) {
new Overloading().x(4.0)
}
}

What is the result?

A.
One

B.
Two

C.
Three

D.
Compilation fails

Explanation:
overloading of the x method fails as the input argument in all three cases are double. To use overloading of methods the argument types must be different.
Note: The Java programming language supports overloading methods, and Java can distinguish between methods with different method signatures. This means that methods within a class can have the same name if they have different parameter lists