Which four options are the characteristics of the original 802.11 protocol? (Choose four.)
A.
Defined DSSS and FHSS as possible methods for modulation
B.
Designed to operate in the 5 GHz ISM frequency spectrum
C.
The most common deployment is three non-overlapping channels that are 20 MHz wide
D.
The protocol sets the maximum throughput at 1 Mb/s or 2 Mb/s
E.
Defined FHSS and OFDM as possible methods for modulation
F.
The most common deployment is three non-overlapping channels that are 22 MHz wide
G.
Designed to operate in the 2.4 GHz ISM frequency spectrum
H.
The protocol sets the maximum throughput at 1 Mb/s
Explanation:
FHSS is still described in the original 802.11 protocol, but another technique was
preferred and adopted by all 802.11 networks: Direct Sequence Spread Spectrum. Instead ofsmall channels and a jumping sequence, the information is sent over a wider channel. This
channel is 22 MHz wide (if the center frequency is 2.412, this channel spans from 2.401 GHz to
2.423 GHz) and does not move (no hopping, which is why the sequence is said to be direct
instead of hopping). Then, over this 22 MHz channel, several bits of information are sent in
parallel. If a source of interference affects part of the channel, it will prevent only the bits sent in
that frequency from reaching the receiver.
In wireless networking a single channel is 20MHz in width. When two channels are bonded, they are a total of 40MHz. 802.11n systems can use either the 20MHz channels or the 40MHz channel.
Shouldn’t it be A,D,F,G ???
It’s about ORIGINAL 802.11 protocol and DSSS which is using 22 MHz…
I got confused with this question..