Refer to the exhibit. A new subnet with 60 hosts has been added to the network. Which subnet
address should this network use to provide enough usable addresses while wasting the fewest
addresses?
A.
192.168.1.56/27
B.
192.168.1.64/26
C.
192.168.1.64/27
D.
192.168.1.56/26
Explanation:
A subnet with 60 host is 2*2*2*2*2*2 = 64 -2 == 62
6 bits needed for hosts part. Therefore subnet bits are 2 bits (8-6) in fourth octet.
8bits+ 8bits+ 8bits + 2bits = /26
/26 bits subnet is 24bits + 11000000 = 24bits + 192
256 – 192 = 64
0 -63
64 – 127