Which series of commands will configure router R1 for LAN-to-LAN communication with router R2? The enterprise network address is 192.1.1.0/24 and the routing protocol in use is RIPv2. (Choose three.)
A.
R1(config)# interface ethernet 0
R1(config-if)# ip address 192.1.1.129 255.255.255.192
R1(config-if)# no shutdown
B.
R1(config)# interface ethernet 0
R1(config-if)# ip address 192.1.1.97 255.255.255.192
R1(config-if)# no shutdown
C.
R1(config)# interface serial 0
R1(config-if)# ip address 192.1.1.4 255.255.255.252
R1(config-if)# clock rate 56000
D.
R1(config)# interface serial 0
R1(config-if)# ip address 192.1.1.6 255.255.255.252
R1(config-if)# no shutdown
E.
R1(config)# router rip
R1(config-router)# network 192.1.1.4
R1(config-router)# network 192.1.1.128
F.
R1(config)# router rip
R1(config-router)# version 2
R1(config-router)# network 192.1.1.0
I belive A is incorrect. B answer is in the same network with e0 on R2. The correct answers are: B D and F.
Please check
A is correct, because the network on e0 of R2 is using subnet
192.1.1.64/26
==> next usable subnet is 192.1.1.128 /26
@hm
You’re right. I thought that LANs must be in the same network, witch is wrong. (LAN-to-LAN communication)
Thanks
First we notice that the ip address of the E0 interface of R2 is 192.1.1.65/26, which has:
+ Increment: 64 (/26 = 1111 1111.1111 1111.1111 1111.1100 0000)
+ Network address: 192.1.1.64
+ Broadcast address: 192.1.1.127
Therefore, the ip address of the E0 interface of R1 cannot belong to this range or the network cannot operate correctly.
In answer A, the ip address of E0 interface of R1 is 192.1.1.129, which does not belong in this range -> A is correct.
In answer B, E0 interface of R1 has the ip address of 192.1.1.97, which belongs in this range -> B is not correct.
The s0 interface of R1 must belong to the same network of s0 interface of R2, which has:
+ Increment: 4 (/30 = 1111 1111.1111 1111.1111 1111.1111 1100)
+ Network address: 192.1.1.4
+ Broadcast address: 192.1.1.7
The ip 192.1.1.5 has been used by s0 of R2 so the only suitable ip address of s0 of R1 is 192.1.1.6 -> C is wrong but D is correct.
Now the last thing we must do is enabling RIP. Because e0 interface of R1 and e0 interface of R2 have the same major network (192.1.1.0/24) so we must use RIP version 2 to support discontiguous network -> F is correct.
For answer E, if we configure 2 networks
R1 (config-router)# network 192.1.1.4
R1 (config-router)# network 192.1.1.128
then these networks will be automatically summarized as 192.1.1.0 network.