The ip subnet zero command is not configured on a router. What would be the IP address of Ethernet 0/0 using the first available address from the sixth subnet of the network
192.168.8.0/29?
A.
192.168.8.25
B.
192.168.8.41
C.
192.168.8.49
D.
192.168.8.113
quoted:
“From the subnet mask, we deduce the increment is 8
First subnet: 192.168.8.0/29
Second subnet: 192.168.8.8/29
3rd subnet: 192.168.8.16/29
4th subnet: 192.168.8.24/2
5th subnet: 192.168.8.32/29
6th subnet: 192.168.8.40/29
7th subnet: 192.168.8.48/29
But the question says that the ip subnet zero is not used, so we can’t use the first subnet. Therefore the “the sixth subnet” will become the seventh subnet, that is 192.168.8.48/29 and its range is 192.168.8.48/29 (network address) to 192.168.8.55/29 (broadcast address) and the first usable host address of this subnet is 192.168.8.49/29.
Hi,
the sub net is /29=248
255-248=7
using the first available address from the sixth subnet of the network
192.168.8.0/29?
1- 192.168.8.0—–network address
2- 192.168.8.1 to 7
3- 192.168.8.14 to 21
4- 192.168.8.28 to 35
5- 192.168.8.35 to 43
6- 192.168.8.49
the answer is C ……..