What two address and subnet combinations are properly matched? (Choose two.)
A.
10.230.33.15/28
B.
10.32.11.67/27
C.
172.16.255.255/14
D.
172.25.44.96/26
E.
192.168.73.223/29
What two address and subnet combinations are properly matched? (Choose two.)
What two address and subnet combinations are properly matched? (Choose two.)
A.
10.230.33.15/28
B.
10.32.11.67/27
C.
172.16.255.255/14
D.
172.25.44.96/26
E.
192.168.73.223/29
B and D
B C D
anyone know the real answer to this?
B and C
Actually, Tsu was right and BCD are correct (just checked this), so you can consider this question fake.
A and E are bradcast addresses. BDC are correct.
You just need to change the addresses to binary and check it yourselfs.
Um, isn’t C also a broadcast address (since last octet is 255)?
172.16.255.255/14
assuming that we can use a /14 subnet in a B class (we shouldn’t):
/14=255.252.0.0 , the magic number is 4. We have
172.0.0.0 as first subnet ID
172.4.0.0 as first subnet ID
172.8.0.0 as first subnet ID
then we have a range of 172.4.0.1 to 172.7.255.254 and 172.7.255.255 is the broadcast address.
No, 172.16.255.255/14 isn’t a broadcast address, just the mask is wrong in a B class 🙂
Sorry: then we have a range of 172.16.0.1 to 172.19.255.254 and 172.19.255.255 is the broadcast address.
:p
Sorry folks,
B/D are right.
C is wrong cause a class B should not have a subnet <16 bit.
B/D are right.
C is wrong cause a class B should not have a subnet <16 bit.
I agree with you Willyx.
So why not A and E? Both of those are broadcast addresses, while B and D are Hosts.
Hosts match a type,
Broadcasts match a type
Which is the correct match?
B/D are right
there are change in dumb
here 12 new questions update 11/4/2016
https://www.dropbox.com/s/t3cst7guoqebjwh/640—911.rar?dl=0
please if any one slutions and sure the questions share with us
http://certcollection.org/forum/topic/285413-ccna-data-center-640-911-exam/
But WHY is B/D correct? That has NOT been explained. As I mentioned, A/E match in the context that they are both broadcasts as well.
B/D are correct, they are both valid IP address within their subnet
A: 10.230.33.15/28 is the broadcast address for the network with subnet mask 255.255.255.240
D: 172.25.44.96/26 is the Network ID based on the subnet mask 255.255.255.192
E: 192.168.73.223/29 is the broadcast address for the network with subnet mask 255.255.255.248
Let me expand on my last comment ..
B/D are correct, they are both are valid HOST IP addresses within their subnet, whereas A,D & E are either the subnet IP or broadcast IP addresses.
Hope they helps?
The question doesnt ask what is valid, it just ask what matches.
BD are valid address. just try use it on your pc
C is also valid