Examine the structure and data in the PRIC E_LIST table: Name Null? Type
———— ————- ——————-PROD_D NOT NULL NUMBER(3)
PROD_PRICE VARCHAR2(10)
PROD_ID PROD PRICE
———– ————————100 $234.55
101 $6,509.75
102 $1,234
in the same format as the PROD_PRICE. Which SQL statement would give the required result?
A.
SELECT TO_CHAR(prod_price* .25.’$99.999.99′) FROM PRICEJLIST:
B.
SELECT TO_CHAR(TO_NUMBER(prod_price)* .25.’$99.999.00′) FROM PRICE_LIST;
C.
SELECT TO_CRAR(TO_NUMBER(prod_price.’S99.999.99′)* .25.’$99.999.00′) FROM
PRICE_LIST:
D.
SELECT TO_NUMBER(TO_NUMBER(prod_price.,$99.999.99′)* .25/$99.999.00′) FROM
PRICE_LIST:
its the same as 1z0-051 Q 89
Nice tip. This is a mess.
as will as . 1Z0-051 (v.1) Q 247
it comes with Explanation:
Yeap goto 1Z0-051 (v.1) Q 247
hi guys
i need fresh dump for 1z0-051
thanks
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