As a Linux system administrator you want to check and print the names of the users having UID >
500, and are not using the bash or csh shell. Which two commands would help you to do so?
(Choose two.)
A.
awk -F: ‘/([-“(bashlcsh)])$/ {if ($3 >500) print $1}’ /etc/passwd
B.
awk -F: ‘/([(bash)]|[(csh)])$/ {if ($3 >500) print $1}’ /etc/passwd
C.
awk -F: ‘/([^(bash)]|[^(csh)])$/ {if ($3 >500) print $1}’ /etc/passwd
D.
awk -F: ‘/([^(noIogin)]|[^(ksh)])$/ {if ($3 >500)print$2}’ /etc/passwd