User jack makes use of the bash shell; his home directory is/export/home/jack.
What is the correct setting of umask, and where should it be set, to allow jack to create a shell
script using the vi editor, that is executable by default?
A.
It is not possible to make a script executable without using the chmod command.
B.
umask value of 0002 set in /etc/profile
C.
umask value of 0002 set in /export/home/jack/.bashrc
D.
umask value of 0722 set in /etc/profile
E.
umask value of 0722 set In /export/home/jack/.bashrc
Explanation:
The user file-creation mode mask (umask) is use to determine the file permission for
newly created files. It can be used to control the default file permission for new files. It is a four-digit octal number.
You can setup umask in /etc/bashrc or /etc/profile file for all users. By default most Unix distro set
it to 0022 (022) or 0002 (002).
In short,
R this questions valid?
correct is : A ; The new file wouldn’t be executable – so you have to use chmod
-rw-rw-rw- 1 root root 0 Oct 16 11:33 umask_0000
-rw-rw-r– 1 root root 0 Oct 16 11:31 umask_0002
-rw–w—- 1 root root 0 Oct 16 11:35 umask_0146
-r–r–rw- 1 root root 0 Oct 16 11:34 umask_0220
–w——- 1 root root 0 Oct 16 11:35 umask_0467
—-r–r– 1 root root 0 Oct 16 11:31 umask_0722
———- 1 root root 0 Oct 16 11:32 umask_0777
Richie please could u help me I need your help
best regards
Ali
Hi Ali
Can you contact Richie?
Thanks in advance
I agree with Richie, file is created with default 666 mode, so umask 0002 result in 664 permission
Definitely A. The permissions would not create an executable file anyway so chmod would be required, not umask.
http://www.oracle.com/technetwork/articles/servers-storage-dev/kornshell-1523970.html
This doc does not mention a way to make scripts executable without the chmod comand.
“A” is valid according to question.. bcz file have no execute permission. so that’s why no 777…..
A is obviously correct answer.
A, when you create a file, it will not be executable, even if you change the /etc/profile to 0002
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