The 224.192.16.1 multicast IP address maps to which multicast MAC address?
A.
01-00-5E-C0-10-01
B.
01-00-5E-40-10-01
C.
01-00-5E-00-10-01
D.
01-00-5E-C0-16-01
The 224.192.16.1 multicast IP address maps to which multicast MAC address?
The 224.192.16.1 multicast IP address maps to which multicast MAC address?
A.
01-00-5E-C0-10-01
B.
01-00-5E-40-10-01
C.
01-00-5E-00-10-01
D.
01-00-5E-C0-16-01
224.192.16.1
Use last 3 octets, find binary value, split each octet into 4 bits each, determine HEX value
192 ==> 01000000 ==> 0100.0000 ==> 40
16 ==> 00010000 ==> 0001.0000 ==> 10
1 ==> 00000001 ==> 0000.0001 ==> 01
01.00.5E.40.10.01
192 – C0
Straight dotted decimal to hex will result in C0-10-01. However with multicast we are keeping the first 25 bits fixed as 01.00.5e and only resolving the lower order 23 bits with the 25th bit staying as 0. The next step is to convert the 2nd, 3rd, and 4th octects of the multicast address. Keep in mind that the 2nd octect holds that 25th bit = 0, so we only resolve the last 7 bits of the 2nd octect.
So 192 in the 2nd octect normally would = 1100000 but in this case we keep the 25th static at 0 and only look at the remaining 7 bits. The results is [0]100000 or in hex it would be 0100 0000 or 0x40.
Continuing on makes the 3rd, and 4th octect equal to what JSlaven had posted. This makes the result correct.