Refer to the exhibit. On the basis of the partial configuration, which two statements are
correct? (Choose two.)
<output omitted>
!
router rip
distribute-list 2 out ethernet 0
distribute-list 1 out
!
access-list 1 permit 10.0.0.0 0.255.255.255
access-list 2 permit 10.0.1.0 0.0.0.255
!
<output omitted>
A.
Only routes matching 10.0.1.0/24 will be advertisedout Ethernet 0.
B.
Only routes 10.0.1.0/24 will be sent out all interfaces.
C.
Only routes 10.0.1.0/24 will be allowed in the routing table.
D.
Only routes matching 10.0.0.0/8 will be advertised out Ethernet 0.
E.
Only routes matching 10.0.0.0/8 will be advertised out interfaces other than Ethernet 0.
F.
All routes will be advertised out interfaces other than Ethernet 0.
Explanation:
In this case, the following algorithm is used when multiple distribute-lists are used:
1. First check which interface is being sent out. If it is Ethernet 0, distribute-list 2 is applied
first. If the network is denied then no further checking is done for this network. But if
distribute-list 2 permits that network then distribute-list 1 is also checked. If both distributelists allow that network then it will be sent out.
2. If the interface is not Ethernet 0 then only distribute-list 1 is applied.
Now let’s take some examples.
+ If the advertised network is 10.0.1.0/24, it willbe sent out all interfaces, including Ethernet
0.
+ If the advertised network is 10.0.2.0/24, it willbe sent out all interfaces, excepting Ethernet
0.
+ If the advertised network is 11.0.0.0/8, it will be dropped.
Note: It is possible to define one interface-specific distribute-list per interface and one
protocol-specific distribute-list for each process/autonomous-system.
(For more information, please read: http://www.cisco.com/en/US/tech/tk365/
technologies_tech_note09186a0080208748.shtml)