Which two networks does the Core1 device have feasible successors for?

Refer to the exhibit.

BigBids Incorporated is a worldwide auction provider. The network uses EIGRP as its routing
protocol throughout the corporation. The network administrator does not understand the
convergence of EIGRP. Using the output of the show ip eigrp topology all-links command, answer
the administrator’s question.
Which two networks does the Core1 device have feasible successors for? (Choose two)

Refer to the exhibit.

BigBids Incorporated is a worldwide auction provider. The network uses EIGRP as its routing
protocol throughout the corporation. The network administrator does not understand the
convergence of EIGRP. Using the output of the show ip eigrp topology all-links command, answer
the administrator’s question.
Which two networks does the Core1 device have feasible successors for? (Choose two)

A.
172.17.0.0/30

B.
172.17.1.0/24

C.
172.17.2.0/24

D.
172.17.3.0/25

E.
172.17.3.128/25

F.
10.140.0.0/24

Explanation:
To understand the output of the “show ip eigrp topology all-links command” command, let’s
analyze an entry (we choose the second entry because it is better for demonstration than the first one)

The first line tells us there is only 1 successorfor the path to 10.140.0.0/24 network but there are
2 lines below. So we can deduce that one line is used for successor and the other is used for
another route to that network. Each of these two lines has 2 parameters: the first one (“156160 or
“157720) is the Feasible Distance (FD) and the second (“128256 or “155160) is the Advertised
Distance (AD) of that route.
The next thing we want to know is: if the route via 172.17.10.2 (the last line) would become the
feasible successor for the 10.140.0.0/24 network. To figure out, we have to compare the
Advertised Distance of that route with the Feasible Distance of the successor’s route, if AD < FD
then it will become the feasible successor. In this case, because AD (155160) < FD (156160) so it
will become the feasible successor. Therefore we can conclude the network 10.140.0.0/24 has 1
feasible successor.
Because the question asks about feasible successor so we just need to focus on entries which
have more paths than the number of successor. In this case, we find 3 entries that are in blue
boxes because they have only 1 successor but has 2 paths, so the last path can be the feasible
successor.
By comparing the value of AD (of that route) with the FD (of successor’s route) we figure out there
are 2 entries will have the feasible successor: the first and the second entry. The third entry has
AD = FD (30720) so we eliminate it.



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