A user reports that they are unable to connect to the network. Upon further investigation, a
technician notices that the user has an IP address/subnet mask combination of 192.168.204.255/24.
The default gateway for the network is 192.168.204.254. Which of the following could the user’s IP
address be changed to so that they could connect to the network?
A.
192.168.204.0/27
B.
192.168.204.1/27
C.
192.168.204.112/24
D.
192.168.204.254/24
Can you explain please? Thanks!
It looks like the answer should have been A because 0 is the network
Answer C is a valid ip address in the /24 or 1-254 subnet.
The answer is C
First the default gateway is 192.168.204.254 (no subnet mask is specified)
Answer A: Cannot be the answer because that would be the network ID for 192.168.204.0/27 (The zero network). The way subnetting is done, the host portion of any subnet cannot equal 0.
Answer B: This would not be suitable because if it were to change it to /27, then the default gateway would be on a different subnet. The last usable IP address would be 192.168.204.30.
Answer D: This cannot be the user IP address, simply because its already been taken by the default gateway.
Hope this helps, any question don’t be afraid to ask.
Happy Hunting
-DVS
Answer A is a different network ID with CIDR /27
Answer B although the IP seem similar, the subnet mask is different CIDR /27
Answer C With a CIDR /24 you have 256 IPs – 2, 1 for the network and 1 for the broadcast leaving you with 254 available IPs in which the GW is already using one (192.168.204.254).
Network: 192.168.204.0
First Host: 192.168.204.1
Last Host: 192.168.204.254 – used by the GW
Broadcast: 192.168.204.255
Answer D – Its the GW.
A and B can not be answewer because /27 on different network.alsso host can not be 0 and 255
D can not be answer because it is the Default getway address