int i, j=0;
i = (3* 2 +4 +5 ) ;
j = (3 * ((2+4) + 5));
System.out.println(“i:”+ i + “\nj”:+j);
What is the result?
A.
Option A
B.
Option B
C.
Option C
D.
Option D
What is the result?
int i, j=0;
i = (3* 2 +4 +5 ) ;
j = (3 * ((2+4) + 5));
System.out.println(“i:”+ i + “\nj”:+j);
What is the result?
Can someone care to explain to me what the hell???
Somebody FUBAR’ed here with the answer selections.
Still, I’d like to point out to all about two things I noticed :
After variables i and j were instantiated as type int and initialized to a value of 0, it then has them being given values again which makes no sense because in this problem, the original i and j are never used.
Removing the value of zero would fix that, though.
Another thing to notice is an apparent typo(intentional?) in the println statement.
there is a Colon outside the final string and preceding the concatenator(+).
I don’t know what the selections are but if the problems I pointed out above are listed, select THAT as your answer.
Or perhaps this is more or less a math problem and if so, then the output would be
i:15
j:33
and that’s if the println statement wasn’t an intentional typo….
“After variables i and j were instantiated as type int and initialized to a value of 0, it then has them being given values again which makes no sense because in this problem, the original i and j are never used.
Removing the value of zero would fix that, though.”
>>> Forget I said that….