Refer to the Exhibit.
You have an MPLS network and you have configured most-fill as a CSPF tiebreaker. Using the
information in the exhibit, which path will be used to signal a new LSP requiring 12 Mbps?
A.
Path 1
B.
Path 2
C.
Path 3
D.
Path 4
Explanation:
the correct answer should be C?
http://www.juniper.net/techpubs/en_US/junos14.2/topics/reference/configuration-statement/random-edit-protocols-mpls.html
The correct answer is D. The CSPF algorithm uses a path with the fewest number of physical hops before considering the load-balancing configuration of the LSP: random, most-fill or least-fill.
minumum number of hop ,then most fill ,answer is D
Asnwer= path=4
simple most-fill with CSPF means go for path=1 but as its dont left 12mbps pipeline so it goes to path=4.
most-fill—Prefer the path with the least available bandwidth (with the minimum available bandwidth ratio). The minimum available bandwidth ratio of a path is the smallest available bandwidth ratio belonging to any of the links in the path.
CSPF the hop count is very important, because the CSPF algorithm is using it as a tie-breaker when equal-cost paths exists.
https://www.netflask.net/jnpr-constrained-shortest-path-first/