which label value does PE1 expect to receive traffic from CE3 for VPN A?

Click the Exhibit button.

In the exhibit, on which label value does PE1 expect to receive traffic from CE3 for VPN A?

In the exhibit, on which label value does PE1 expect to receive traffic from CE3 for VPN A?

A.
2002

B.
3001

C.
3002

D.
2001



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Nguyen Duc Hoa

Nguyen Duc Hoa

B is correct.

fanziii

fanziii

Agreed. Correct answer is B.

CCIP

CCIP

Can either of you explain? I still think A is Correct :
2000+3-1=2002

neo

neo

Now I’m confused totally… Formula is Local Site ID + remote Label Base – Remote offset

Q is what label PE1 is expecting from CE3(PE2).

Then label = 2+3000-1 = 3001

Isn’t it ??

networkmanagers

networkmanagers

OK . we will fix from A to B

neo

neo

Hi guys! Some of you have already given the exam.. What is the correct anwer ??

I am not sure about answer 3001.. MY logic was driving me towards 3001 but I cant discard 2002 as well.

Can anyone make us clear and set a concrete standpoint ?

Renzo

Renzo

la respuesta correcta es 2002 A, tener en cuenta que en L2VPN no se anuncia el label vpn , cada PE debe calcular el label vpn (outgoing label) la cual sera usada para enviar trafico hacia su CE remote. en este caso en particular implicitamente te dice que label debe usar PE2 para enviar trafico hacia CE1 , (PE2 – label outgoing = PE1 label ingoing).

RL

RL

L2VPN label = Label-Base(remote) + Site-Id(Local) – Label-Offset(remote)

DanyG

DanyG

When transmitting from PE2 to PE1 formula is as follows:
Remote Base ( 2000 ) + Local Site ( 3 ) – Remote Offset ( 1 ) => 2002

When receiving, formula is Local Base + Remote Site – Local Offset so P2 expects:
Local Base ( 2000 ) – Local Offset ( 1 ) + Remote Site ( in this case PE2 site id = 3 ) => 2002

So I think A -> 2002 is the correct answer

chandima

chandima

Answer is A ,

The formular to calculate the inner label to receive traffic at CE1 from CE 3 ( asuming the CE3 belongs to VPN-A)

Inner Label value = label-base-local + Remote site ID – Label offet local.

for PE1 , Inner lable = 2000+3-1
= 2002

what happens is when traffic sends from PE2 router 2002 inner label is pushed in to the MPLS packet and pass througt P1 and P2 to PE1. PE 1 finally looked the inner label 2002 and pass the packet to VPN A

DS

DS

Pleae refer JNCIS for this querry ….. just search with label offset you will get scenario explained in details.

Here PE1 is expecting label from PE2, now PE2 outgoing label should be calculated as per formula.

Label = Label base remote – label offset remote + site ID Local

Remember outgoing label is calculated based on advertised route by remote PE which is PE1 here.

Label = 2000-1+3 = 2001 …………. This is one of the exam question.

DS

DS

Sorry above result is 2002 as per calculation.

rawmaterial

rawmaterial

I also agree answer show be A.

For PE2 to send traffic for CE1 on VPN A. PE2 first look at the received advertisement from PE-1, PE-2 then sends frames destined for CE1 using an inner label of 2002 (Remote base(2000) + local site-id(3) – Remote offset(1)).

So 2000+3-1 = 2002 is the answer.

PF

PF

Answer is A

JNCIS study Guide page 658

@dev-null Nice link