The chance of a hard drive failure is known to be once every four years. The cost of a new hard drive is $500.
EF (Exposure Factor) is about 0.5. Calculate for the Annualized Loss Expectancy (ALE).
A.
$62.5
B.
$250
C.
$125
D.
$65.2
The chance of a hard drive failure is known to be once every four years. The cost of a new hard drive is $500.
EF (Exposure Factor) is about 0.5. Calculate for the Annualized Loss Expectancy (ALE).
The chance of a hard drive failure is known to be once every four years. The cost of a new hard drive is $500.
EF (Exposure Factor) is about 0.5. Calculate for the Annualized Loss Expectancy (ALE).
A.
$62.5
B.
$250
C.
$125
D.
$65.2
Answer should be A
Google for Annualized Loss Expectancy (ALE) Formula
Ans. A
4/0.5 = 8
500/8 = 62.6
A.
answer A is indeed correct, but what does this have to do with CEHv9. This is CISSP Domain 1 Security Risk Management
B