View the Exhibit and examine the description of EMPLOYEES and DEPARTMENTS tables.
You want to display the EMPLOYEE_ID, LAST_NAME, and SALARY for the employees who get the maximum salary in their respective departments. The following SQL statement was written:
WITH
SELECT employee_id, last_name, salary
FROM employees
WHERE (department_id, salary) = ANY (SELECT *
FROM dept_max)
dept_max as ( SELECT d.department_id, max(salary)
FROM departments d JOIN employees j
ON (d.department_id = j.department_id)
GROUP BY d.department_id);
Which statement is true regarding the execution and the output of this statement?
A.
The statement would execute and give the desired results.
B.
The statement would not execute because the = ANY comparison operator is used instead of =.
C.
The statement would not execute because the main query block uses the query name before it is even created.
D.
The statement would not execute because the comma is missing between the main query block and the query name.
WITH
dept_max as ( SELECT d.department_id, max(salary)
FROM departments d JOIN employees j
ON (d.department_id = j.department_id)
GROUP BY d.department_id),
dept_max2 as (select department_id from dept_max),
dept_max3 as (select department_id from dept_max2)
SELECT employee_id, last_name, salary
FROM employees
WHERE (department_id, salary) = ANY (SELECT *
FROM dept_max);
=ANY is okay for lists in where clause