See the Exhibit and examine the structure of the CUSTOMERS table:
Using the CUSTOMERS table, you need to generate a report that shown the average credit limit for customers
in WASHINGTON and NEW YORK.
Which SQL statement would produce the required result?
A.
SELECT cust_city, AVG(cust_credit_limit)
FROM customers
WHERE cust_city IN (‘WASHINGTON’,’NEW YORK’)
GROUP BY cust_credit_limit, cust_city;
B.
SELECT cust_city, AVG(cust_credit_limit)
FROM customers
WHERE cust_city IN (‘WASHINGTON’,’NEW YORK’)
GROUP BY cust_city,cust_credit_limit;
C.
SELECT cust_city, AVG(cust_credit_limit)
FROM customers
WHERE cust_city IN (‘WASHINGTON’,’NEW YORK’)
GROUP BY cust_city;
D.
SELECT cust_city, AVG(NVL(cust_credit_limit,0))
FROM customers
WHERE cust_city IN (‘WASHINGTON’,’NEW YORK’);
Explanation:
Creating Groups of Data: GROUP BY Clause Syntax
You can use the GROUP BY clause to divide the rows in a table into groups. You can then use the group
functions to return summary information for each group.
In the syntax:group_by_expression Specifies the columns whose values determine the basis for grouping rows Guidelines
· If you include a group function in a SELECT clause, you cannot select individual results as well, unless the
individual column appears in the GROUP BY clause. You receive an error message if you fail to include the
column list in the GROUP BY clause.
· Using a WHERE clause, you can exclude rows before dividing them into groups.
· You must include the columns in the GROUP BY clause.
· You cannot use a column alias in the GROUP BY clause.