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malvern

malvern

count++ is unreachable hence compilation error

Sucuk

Sucuk

Answer is A. compilation fails

rfvc

rfvc

A is correct, but i dont know why. because continue have colon instead of semicolon. and then count++ is unreachable code.

jeronimo

jeronimo

A: PORQUE EL COPILADOR DETECTA QUE NUNCA VA LLEGAR AL COUNT

AntonioP

AntonioP

A is the correct answer, but no tag has been defined for continue: . So I’m doubtful about what’s the right answer

Bob

Bob

A, but i am not sure, if you compile it, it will print 0 found due to the Continue;, however due to logic Given the code then yes there is an compilation error.