Your network contains a System Center 2012 Configuration Manager environment.
You need to create a report that lists all of the client computers that do not have an
Application named App1 instated.
Which query should you use to create the report?
A.
SELECT SYS.Netbios_Name0, ARP.DisplayName0
FROM v_R_System AS SYS INNER JOIN
v_GS_ADD_REMOVE_PROGRAMS AS ARP ON SYS.ResourceID = ARP. ResourceID
WHERE ARP.DisplayName0 NOT IN (‘App1’)
B.
SELECT SYS.Netbios_Name0 from v_R_System SYS
WHERE SYS.ResourceID IN
(SELECT SYS.ResourceID
FROM v_R_System AS SYS INNER JOIN
v_GS_ADD_REMOVE_PROGRAMS AS ARP ON SYS.ResourceID – ARP.ResourceID.
WHERE ARP.
DisplayName0 = ‘App1’)
C.
SELECT SYS.Netbios_Name0 from v_R_System SYS
WHERE SYS.ResourceID NOT IN
(SELECT SYS.ResourceID
FROM v_R_System AS SYS INNER JOIN
v_GS_ADD_REMOVE_PROGRAMS AS ARP ON SYS.ResourceID = ARP.ResourceID
WHERE ARP.
DisplayName0 = ‘App1’)
D.
SELECT SYS.Netbios_Name0, ARP.DisplayName0
FROM v_R_System AS SYS INNER JOIN
V_GS_ADD_REMOVE_PROGRAMS AS ARP ON SYS.ResourceID – ARP.ResourceID
WHERE ARP.DisplayName0 NOT LIKE ‘App1’
Explanation:
The inner expression listed below would result in an empty result if the client
computer does not have an application named App1.
Inner expression:
(SELECT SYS.ResourceID
FROM v_R_System AS SYS INNER JOIN
v_GS_ADD_REMOVE_PROGRAMS AS ARP ON SYS.ResourceID = ARP.ResourceID
WHERE ARP.
DisplayName0 = ‘App1’)