Which of the following would the security engineer set as the subnet mask for the servers below to utilize host addresses on separate broadcast domains?

Which of the following would the security engineer set as the subnet mask for the servers below to
utilize host addresses on separate broadcast domains?
Server 1: 192.168.100.6
Server 2: 192.168.100.9
Server 3: 192.169.100.20

Which of the following would the security engineer set as the subnet mask for the servers below to
utilize host addresses on separate broadcast domains?
Server 1: 192.168.100.6
Server 2: 192.168.100.9
Server 3: 192.169.100.20

A.
/24

B.
/27

C.
/28

D.
/29

E.
/30

Explanation:
Using this option will result in all three servers using host addresses on different broadcast
domains.



Leave a Reply 2

Your email address will not be published. Required fields are marked *

four − three =


some_coder

some_coder

Each / refers to the mask length.

We only care about our final octet, so the mask will need to be *at least* 24 in length.

Why?

Because 255.255.255.X is at least 24 ones. Count them:

255 = 1111 1111

3 each 255’s = 8*3 = 24

The question is asking us to consider what kind of subnet mask will force all 3 of those IP addresses to be on different subnets. Different subnets mean different broadcast domains, which means less overall traffic for the switch/router. This is why subnet masking is A Good Thing.

A subnet mask of 255.255.255.248, or /29, looks like the following:
1111 1111 | 1111 1111 | 1111 1111 | 1111 1XXX

Which will force subnets the 3 IP addresses, by the final octet, to necessarily be on different subnets. I suppose that /30 would do the same trick, but this is the best I can figure out to understand the answer’s rationale.

0000 0110 – 6
0000 1001 – 9
0001 0100 – 20

A subnet mask smaller than /29 would put at least .6 and .9 on the same subnet. /29 is just the right size.

David Hill

David Hill

Thank you for your better answer!